# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def flipEquiv(self, root1: Optional[TreeNode], root2: Optional[TreeNode]) -> bool:
def dfs(root1, root2):
if root1 == root2 or (root1 is None and root2 is None):
return True
if root1 is None or root2 is None or root1.val != root2.val:
return False
return (dfs(root1.left, root2.left) and dfs(root1.right, root2.right)) or (
dfs(root1.left, root2.right) and dfs(root1.right, root2.left)
)
return dfs(root1, root2)