Обновлено: 2024-03-12
1 мин
Содержание
class Solution:
def countArrangement(self, n: int) -> int:
def dfs(i):
nonlocal res, n
if i == n + 1:
res += 1
return
for j in match[i]:
if not vis[j]:
vis[j] = True
dfs(i + 1)
vis[j] = False
res = 0
vis = [False] * (n + 1)
match = defaultdict(list)
for i in range(1, n + 1):
for j in range(1, n + 1):
if j % i == 0 or i % j == 0:
match[i].append(j)
dfs(1)
return res