Обновлено: 2024-03-12
1 мин

Содержание

ps = []
for i in range(1, 10**5 + 1):
    s = str(i)
    t1 = s[::-1]
    t2 = s[:-1][::-1]
    ps.append(int(s + t1))
    ps.append(int(s + t2))
ps.sort()


class Solution:
    def minimumCost(self, nums: List[int]) -> int:
        def f(x: int) -> int:
            return sum(abs(v - x) for v in nums)

        nums.sort()
        i = bisect_left(ps, nums[len(nums) // 2])
        return min(f(ps[j]) for j in range(i - 1, i + 2) if 0 <= j < len(ps))
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