Обновлено: 2024-03-12
1 мин
Содержание
ps = []
for i in range(1, 10**5 + 1):
s = str(i)
t1 = s[::-1]
t2 = s[:-1][::-1]
ps.append(int(s + t1))
ps.append(int(s + t2))
ps.sort()
class Solution:
def minimumCost(self, nums: List[int]) -> int:
def f(x: int) -> int:
return sum(abs(v - x) for v in nums)
nums.sort()
i = bisect_left(ps, nums[len(nums) // 2])
return min(f(ps[j]) for j in range(i - 1, i + 2) if 0 <= j < len(ps))