2428. Maximum Sum of an Hourglass
Содержание
class Solution:
def maxSum(self, grid: List[List[int]]) -> int:
m, n = len(grid), len(grid[0])
res = 0
for i in range(1, m - 1):
for j in range(1, n - 1):
s = -grid[i][j - 1] - grid[i][j + 1]
s += sum(
grid[x][y] for x in range(i - 1, i + 2) for y in range(j - 1, j + 2)
)
res = max(res, s)
return res