2282. Number of People That Can Be Seen in a Grid
Содержание
class Solution:
def seePeople(self, heights: List[List[int]]) -> List[List[int]]:
def f(nums: List[int]) -> List[int]:
n = len(nums)
stk = []
res = [0] * n
for i in range(n - 1, -1, -1):
while stk and stk[-1] < nums[i]:
res[i] += 1
stk.pop()
if stk:
res[i] += 1
while stk and stk[-1] == nums[i]:
stk.pop()
stk.append(nums[i])
return res
res = [f(row) for row in heights]
m, n = len(heights), len(heights[0])
for j in range(n):
add = f([heights[i][j] for i in range(m)])
for i in range(m):
res[i][j] += add[i]
return res