2266. Count Number of Texts
Содержание
mod = 10**9 + 7
f = [1, 1, 2, 4]
g = [1, 1, 2, 4]
for _ in range(100000):
f.append((f[-1] + f[-2] + f[-3]) % mod)
g.append((g[-1] + g[-2] + g[-3] + g[-4]) % mod)
class Solution:
def countTexts(self, pressedKeys: str) -> int:
res = 1
for ch, s in groupby(pressedKeys):
m = len(list(s))
res = res * (g[m] if ch in "79" else f[m]) % mod
return res