2182. Construct String With Repeat Limit
Содержание
class Solution:
def repeatLimitedString(self, s: str, repeatLimit: int) -> str:
cnt = [0] * 26
for c in s:
cnt[ord(c) - ord("a")] += 1
res = []
j = 24
for i in range(25, -1, -1):
j = min(i - 1, j)
while 1:
x = min(repeatLimit, cnt[i])
cnt[i] -= x
res.append(ascii_lowercase[i] * x)
if cnt[i] == 0:
break
while j >= 0 and cnt[j] == 0:
j -= 1
if j < 0:
break
cnt[j] -= 1
res.append(ascii_lowercase[j])
return "".join(res)