1940. Longest Common Subsequence Between Sorted Arrays
Содержание
class Solution:
def longestCommomSubsequence(self, arrays: List[List[int]]) -> List[int]:
def common(l1, l2):
i, j, n1, n2 = 0, 0, len(l1), len(l2)
res = []
while i < n1 and j < n2:
if l1[i] == l2[j]:
res.append(l1[i])
i += 1
j += 1
elif l1[i] > l2[j]:
j += 1
else:
i += 1
return res
n = len(arrays)
for i in range(1, n):
arrays[i] = common(arrays[i - 1], arrays[i])
return arrays[n - 1]