2218. Maximum Value of K Coins From Piles
Содержание
class Solution:
def maxValueOfCoins(self, piles: List[List[int]], k: int) -> int:
presum = [list(accumulate(p, initial=0)) for p in piles]
dp = [0] * (k + 1)
for s in presum:
for j in range(k, -1, -1):
for idx, v in enumerate(s):
if j >= idx:
dp[j] = max(dp[j], dp[j - idx] + v)
return dp[-1]