2106. Maximum Fruits Harvested After at Most K Steps

class Solution:
    def maxTotalFruits(self, fruits: List[List[int]], startPos: int, k: int) -> int:
        res = i = s = 0
        for j, (pj, fj) in enumerate(fruits):
            s += fj
            while (
                i <= j
                and pj
                - fruits[i][0]
                + min(abs(startPos - fruits[i][0]), abs(startPos - fruits[j][0]))
                > k
            ):
                s -= fruits[i][1]
                i += 1
            res = max(res, s)
        return res