1851. Minimum Interval to Include Each Query
Содержание
class Solution:
def minInterval(self, intervals: List[List[int]], queries: List[int]) -> List[int]:
n, m = len(intervals), len(queries)
intervals.sort()
queries = sorted((x, i) for i, x in enumerate(queries))
res = [-1] * m
pq = []
i = 0
for x, j in queries:
while i < n and intervals[i][0] <= x:
a, b = intervals[i]
heappush(pq, (b - a + 1, b))
i += 1
while pq and pq[0][1] < x:
heappop(pq)
if pq:
res[j] = pq[0][0]
return res