1830. Minimum Number of Operations to Make String Sorted
Содержание
n = 3010
mod = 10**9 + 7
f = [1] + [0] * n
g = [1] + [0] * n
for i in range(1, n):
f[i] = f[i - 1] * i % mod
g[i] = pow(f[i], mod - 2, mod)
class Solution:
def makeStringSorted(self, s: str) -> int:
cnt = Counter(s)
res, n = 0, len(s)
for i, c in enumerate(s):
m = sum(v for a, v in cnt.items() if a < c)
t = f[n - i - 1] * m
for v in cnt.values():
t = t * g[v] % mod
res = (res + t) % mod
cnt[c] -= 1
if cnt[c] == 0:
cnt.pop(c)
return res