1671. Minimum Number of Removals to Make Mountain Array
Содержание
class Solution:
def minimumMountainRemovals(self, nums: List[int]) -> int:
n = len(nums)
left = [1] * n
right = [1] * n
for i in range(1, n):
for j in range(i):
if nums[i] > nums[j]:
left[i] = max(left[i], left[j] + 1)
for i in range(n - 2, -1, -1):
for j in range(i + 1, n):
if nums[i] > nums[j]:
right[i] = max(right[i], right[j] + 1)
return n - max(a + b - 1 for a, b in zip(left, right) if a > 1 and b > 1)