1496. Path Crossing

class Solution:
    def isPathCrossing(self, path: str) -> bool:
        i = j = 0
        vis = {(0, 0)}
        for c in path:
            match c:
                case 'N':
                    i -= 1
                case 'S':
                    i += 1
                case 'E':
                    j += 1
                case 'W':
                    j -= 1
            if (i, j) in vis:
                return True
            vis.add((i, j))
        return False