2098. Subsequence of Size K With the Largest Even Sum
On This Page
class Solution:
def largestEvenSum(self, nums: List[int], k: int) -> int:
nums.sort()
res = sum(nums[-k:])
if res % 2 == 0:
return res
n = len(nums)
mx1 = mx2 = -inf
for x in nums[: n - k]:
if x & 1:
mx1 = x
else:
mx2 = x
mi1 = mi2 = inf
for x in nums[-k:][::-1]:
if x & 1:
mi2 = x
else:
mi1 = x
res = max(res - mi1 + mx1, res - mi2 + mx2, -1)
return -1 if res % 2 else res