1900. The Earliest and Latest Rounds Where Players Compete

Updated: 2024-03-12
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LeetCode problem 1900

class Solution:
    def earliestAndLatest(
        self, n: int, firstPlayer: int, secondPlayer: int
    ) -> List[int]:
        # dp[i][j][k] := (earliest, latest) pair w/ firstPlayer is i-th player from
        # Front, secondPlayer is j-th player from end, and there're k people
        @functools.lru_cache(None)
        def dp(l: int, r: int, k: int) -> List[int]:
            if l == r:
                return [1, 1]
            if l > r:
                return dp(r, l, k)

            a = math.inf
            b = -math.inf

            # Enumerate all possible positions
            for i in range(1, l + 1):
                for j in range(l - i + 1, r - i + 1):
                    if not l + r - k // 2 <= i + j <= (k + 1) // 2:
                        continue
                    x, y = dp(i, j, (k + 1) // 2)
                    a = min(a, x + 1)
                    b = max(b, y + 1)

            return [a, b]

        return dp(firstPlayer, n - secondPlayer + 1, n)