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Given a non-negative integer x, return the square root of x rounded down to the nearest integer. The returned integer should be non-negative as well.
You must not use any built-in exponent function or operator.
For example, do not use
pow(x, 0.5) in c++ or
x ** 0.5 in python.
Input: x = 4 Output: 2 Explanation: The square root of 4 is 2, so we return 2.
Input: x = 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since we round it down to the nearest integer, 2 is returned.
class Solution: def mySqrt(self, x: int, div=2) -> int: s = x // div s1 = (s + div) // 2 if s1 * s1 > x: s1 = self.mySqrt(x, s1) return s1 else: return s1